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Today we study the Calculus (I)
The topic is the Definite Integral
Maybe you can ask yourself a question
how to compute
the area of the curve trapezoid
Now we look at the figure
means the area
We have known the given idea
If a rectangular is given
the corresponding height f(x) equals h
At this time
the rectangular area formula
equals base time height
In this figure
the corresponding base means
b minus a
the corresponding height is h
so we have known
the corresponding formula
Now the rectangle idea means
rectangle area is approximate
to replace the curve trapezoid area
How to replace
So now look at
if we have five small rectangles
The corresponding area is
approximate to the trapezoid area
If there are ten small rectangles
one two three four five
until ten
At this time
the sum of the areas of the ten small rectangles
is approximate to replace the curve trapezoid area
How to do this idea
So now look at the following idea
If we divide the curve trapezoid
into a number of small rectangles
This means
the number of small rectangles is infinity
At this time
the rectangle's width gradually reduces
then how to find the area of A
Now look at the figure
Yes
maybe we have infinite small rectangles
At this time
means the number of rectangles is infinity
So now look at the figure
If we divide so many small rectangles
we can get
the corresponding area ΔAi
And do the summation
of the small rectangles
How to get it
There are the following four steps
Look at Step 1
means segmentation
Segmentation means
the beginning point a equals x0
the end point b is equal to xn
at this time
divided x1, x2 and xn-1
into the closed interval
So now become
this a, b closed interval become n intervals
And then
how to do
We can get the corresponding interval
distance Δxi
equals the right point xi
minus the left point xi-1
Step 2
how to do
Yes
the approximation
At this time
the corresponding area of the rectangle ΔAi
is approximate to
the area of the rectangle
Look at this
classical rectangle
the corresponding base means
xi minus xi-1
means corresponding our base
Look at the height
any fixed point ξi
ξi is given
We can take the value f(ξi)
means our height
At this time
the area means
base time the height
How to do
And then
Step 3
do the summation
The summation of this area
is approximate
to the summation f(ξi) time Δxi
Why not equal
Yes
if the i from 1 to n
if n is enough large
then think
the area value is
approximate to our real area
So do the step 4
getting the limit
how to get the limit
The limit A equals the limit
λ tends to 0
summation i from 1 to n
if n is enough large
This means
λ equals
the maximum value of
the interval distances Δx1 Δx2 until Δxn
if λ tends to 0
At this time
n tends to positive infinity
means there are some tendency
If there is some tendency
means the limit exist
It is a real number
The real number is our area of the curve trapezoid
So try to understand the 4 steps
So now look at
the concrete definition
If the region A is bounded by
bounded by y equals f(x)
larger than 0
means above the x-axis
And x equals a
x equals b
and y equals 0
bounded by the four curves
Some are lines
And how to find the area of A
The area of A is denoted as I
We have the following idea
means the definite integral
from a to b
f(x) dx is our integral
Integral equals
the limit of summation f(ξi) time Δxi
Summation
pay attention to
i from 1 to n
Look at the tendency
λ tends to 0
Pay attention to
the corresponding signs
Look at a
a is called our lower limit
because it is low
So means lower limit
How about b
Corresponding
upper limit
so means upper limit
Look at f(x)
Yes it is a function
in this signs
means integral function
How about x
It is variable
it is called integral variable
Look at the sum
The sum means integral sum
So try to remember
the signs and understand the formula
If we try to find the area of
the curve trapezoid
how to change the question
into the integral
means definite integral
So now according to the idea
we will do some examples
Look at Example 1
Try to find
the area of the region
he region bounded by
y equals x square
and x equals 1
and x-axis
How to do
Do you remember
the formula definite integral
This means the area of the region
Try to find
some value of definite integral
So this means x square
our integral function
corresponding
lower limit is 0
the upper limit is 1
x is our integral variable
This means the area equals
the value of definite integral
So we have the following concrete steps
Let the beginning point x0 equals 0
and end point xn equals 1
Divide
means x1, x2,…,xn-1
So we can get
he corresponding figure
y equals x square
and x equals 0
x equals 1
Above x-axis
means the corresponding region
the region
how to do
Segmentation
the first step
ok
So
we have the corresponding
so many small rectangles
Look at the classical rectangles
Taking the point xi equals i over n
Why
Look at the first
The end point means 0 over n
means number 0
This point 1 over n
the last point means n over n
So corresponding
in this interval
the point is i over n
So taking xi equals i over n
corresponding Δxi
means the distance of the interval
equals 1 over n
Why
Because between 0 and 1
the distance is 1
How many parts
Yes
n parts
So the distance of every interval is
1 over n
n is fixed ok
n is sometimes some variable
i from 1 2 until n
We let ξi equals xi
ξi means some fixed point
into the given interval
You can select
left point or right point
or any point between the end points
So now we take
ξi equals right point xi
i from 1, 2 until n
And then we have
the sum integral
We have summation i form 1 to n
f(ξi) Δxi
Thinking of the question
Look at
what is our f(ξi)
Yes
ξi equals xi
f(ξi) what
Yes
f means x square
variable square
So this part means ξi square
How about Δxi
Δxi
yes
the interval distance means
1 over n
So we have f(ξi)
means the variable square
So ξi square time Δxi
Taking the given values
xi means corresponding
i over n
Δxi 1 over n
Taking the numbers
We can get ok
summation i from 1 to n
bracket i over n square
time 1 over n
Pay attention to
in the summation formula
n is fixed
What is changeable
i
pay attention to i
so i changeable
Go on compute this expression
taking the concrete number n cube
Summation
summation what
Summation i
why
i is changeable
So now summation i square
So we only need to compute
summation i square
According to the basic knowledge
we know the summation i square
Do you remember the basic formula in your high school
y over n cube
summation i square equals
equals n time bracket n plus 1
time bracket double n plus 1 over 6
So now we have got
the integral summation
How to do
Try to get the limit
So now we can get
1 over 6 is a constant taken out
So in the first term means 1 over 6
Now look at
the term n cube
n cube
n,n delete 1 power
n plus 1 over n
equals 1 plus 1 over n
This term
double n plus 1 over n
equals 2 plus 1 over n
So now the integral sum is
a function of n
If λ tends to 0
do you remember λ
Yes
λ is the maximum value of
the interval distance
So λ tends to 0
This means
n tends to positive infinity
So this gives you idea
how to compute the limit
So the last step
The area of the region means
equals the value of definite integral
from 0 to 1
x square dx
This equals
do you remember the last step
Step 4
equals the limit summation
λ tends to 0
Now look at the summation
Yes
the summation is a function of n
So taking the expression of n
λ tends to 0
means n tends to positive infinity
Why you write it n
Because in this expression
the variable is n
So we need to write it n how to change
So n tends to positive infinity
So how to compute
Yes
equals 1 by 3
Why
Yes
1 over 6 time 1 plus 0 time 2 plus 0
so 2 over 6
together equals 1 over 3
It is our final value
means it is our area of the region
From the question we can find
the area equals this expression
It is a real number
means concrete number
The integral from 0 to 1
is approximate to this expression
Why
Do you remember this is integral sum
The sum means sum expression of n
n is changeable
so not equal
means is close to
not equal
so equals this expression
n how to change
n tends to positive infinity
Why
Because if n takes different values
at this time
the area means definite integral
has different approximation accuracies
n is enough large
At this time
we can get
the limit is our definite integral
means it is our area
Try to understand the idea
So now we look at Example 2
Try to evaluate
the definite integral
by using a regular partition
Do you know partition
Yes
partition means our step 1
segmentation
So now look at the idea
We taking in example 1
Δx equals 1 over n
In this question
Δx equals 5 over n
Why
Can you tell me
Why is 5
Yes
you should pay attention to
the upper limit
and lower limit values
Upper limit equals 3
lower limit equals minus 1
How about the distance of the interval
3 minus minus 2 means 3 plus 2
equals 5
So at this time
the given closed interval
is divided by n intervals
Every interval distance is 5 over n
Taking ξi
the given point equals xi
as our sample point
means some fixed point
in the closed interval
Try to understand 5 over n and xi
Now look at the figure ok
y equals x plus 3
How to find the corresponding area
Taking the following point
taking the original point x0 equals
lower limit means minus 2
The xn equals our upper limit means 3
How to write it
x1 equals beginning point plus the
interval distance
xn equals the left end point plus
5 over n time 2
and go on
How to do
Blah blah blah
xi equals
the left end point minus 2 plus
5 over n time i
We can take the different points
Using the idea
pay attention to xi corresponding values
So now
we have f(ξi)
Do you remember
f(x) equals x plus 3
So f(ξi) equals (f(ξi)
f(xi) f(xi) plus 3
Together
xi
do you remember
minus 2 plus i time 5 over n
minus 2 plus 3 equals positive 1
So equals 1 plus i time 5 over n
Try to understand f(ξi)
It is our height
Do the sum
integral sum
The sum equals f(ξi) time Δxi
What is our f(ξi)
Yes
f(xi)
what is our Δxi
Do you remember
Yes
5 over n
Taking the corresponding values
f(ξi) equals this number ok
Δxi
Try to do the summation
Have the similar idea in Example 1
Pay attention to the sum
What is changeable
Pay attention to i
Yes
i is changeable
How about n
From 1 to n
This means n is fixed
So i is changeable
So now we do the summation
equals 5 plus 25 over 2
plus 25 over double n
This is our sum
integral sum
Finally the sum is a function of n
not i
Why
Because i we have computed
So corresponding
Definite integral means our area ok
equals the limit of integral sum
Taking in Corresponding
if λ tends to 0
equals what
Equivalent to
n tends to positive infinity
Pay attention to this formula
In this formula
if n tends to positive infinity
at this time
constant is still constant equals itself
n tends to positive infinity
This term equals 0
So the final result
the limit equals 5 plus 25 over 2
together equals 35 over 2
It is our final result
means the definite integral value
Try to understand the idea
how to take the integral sum
how to compute the limit
According to the two examples
we try to get ome summary of
the definite integral
Look at property 1
if a equals b
You can think the figure in your mind
If a equals b
at this time
a equals b
this means 0
Why
if a equals b
at this time
the corresponding figure
the region become one segment
The area of segment equals 0
So from 1 to 1
3 to 3
4 to 4
equals 0
Why
At this time
the geometrical meaning means
the area of the segment
so equals 0
Now look at
if a larger than b
This means from a to b
f(x) dx equals corresponding b, a, minus
How to understand
Try to understand
the formula using the limit property
From a to b
from b to a
They are corresponding
if you equals 9
I will equals minus 9
Change the order of
upper limit and lower limit
change the order
So a b become b a minus
Try to remember
if a function has definite integral
What means has definite integral
This means the limit exists
And then
if we don't consider the values of a and b
We don't care the values
Maybe a is larger than b
Maybe a is less than b
Maybe a equals b
We don't care which one is bigger
And then
we will have the following properties
Five properties
so now look at Property 1
If a, b integral function
f(x) plus or minus g(x) equals what
Yes
equals the corresponding summation
or minus of the two definite integrals
How to prove
You can prove by yourself
using the limit idea
Now look at Property 2
a b
the integral function is k time f(x)
k is a constant
k is a constant means
k is taken out
from the definite integral
equals k time the definite integral
where k is a constant number
The property 1 and property 2 together mean
the linear characteristics
Try to understand
in the future computation
we always use the linear property
So now look at Property 3
If c between a and b
means c is a number between a and b
How to write it
Yes
the definite integral a, b
f(x) dx
equals from a to b
How to write it c
Any c
Yes c
from a c plus c b
The property means interval additivity
c is a number between a and b
We can prove in the future
c is any real number for the formula
is always true
This means interval additivity
Now look at Property 4
If the integral function
is a special function equals 1
You can think it
In your mind at this time
the curve trapezoid becomes a
regular rectangle
Yes
at this time equals base
The base means b minus a
How about the height
Yes
the height is constant
always equals 1
So the final value is
b minus a time 1
so equals b minus a
Now we study the last property 5
Property 5 means
if f(x) is non-negative
Negative means less than 0
Non-negative means large than or equals 0
At this time
a b f(x) dx
it is our definite integral
still non-negative
Still non-negative
this means "sign preserving" property
Try to understand the 5 properties
So now
we will use the 5 properties
and the definition of definite integral
Try to answer the questions
Look at the question 1
Question 1 means try to find the limit
The limit
pay attention to this
n tends to positive infinity
Limit the first term
1 over n plus 1
The second term
1 over n plus 2
plus blah blah blah
plus the last term 1 over n plus n
Maybe you can write it like this
n tends to positive infinity
So the first limit equals 0
ok
The second equals 0
blah blah blah
Together
the last equals 0
0 0 plus 0
infinite 0
together equals 0
Some students write it
If in your test
you write it like this
It is wrong
Why
Do you remember
if the limit of summation equals
the summation of the limit
The given condition
what
Yes
the number of expression
means the number of limit is finite
Now we can count
1 2 3 4 … n
How many
n
n tends to positive infinity
so using the limit property is wrong
Now how to do
We have the following idea
We can write it the limit
in this expression
Pay attention to n plus 1
n plus 2 until n plus n
Thinking yourself
the integral summation
yes
f(ξi) time Δxi
So we can write it Δxi
Write it 1 over n
How to write it 1 over n
means doesn't change ok
Equivalent to taking n
from every term
The first term
taking n out
become 1 plus 1 over n
the second term
taking n out
n taken out become 1
This term become 2 over n
until the last term
Yes how to write it
f(ξi) means f(xi)
What is our i
How to find it
We can write it
Copy the limit
n tends to positive infinity
summation 1 plus 1 over n
1 plus 2 over n
Blah blah blah
Try to find the regulation
Try to find the rule
The rule means 1 plus i
Yes
i here
1 2 3 4 until n
So this is our regulation i over n
time 1 over n
Yes
so now we find it the ξi
ξi means i over n
So we can write it
the limit summation
become the definite signs
How about f(ξi)
f(ξi) means our f(x)
1 over 1 plus ξi
This means
1 over 1 plus x
1 over n means our interval distance
We can write it
d integral variable
So write it dx
So pay attention to limit summation
corresponding
the definite signs
f(ξi) corresponding
our integral function
1 over n doesn't change
1 over n is our interval distance
We can write it corresponding
x is our interval variable
So write it this form
We have known the corresponding
the definite integral anti-derivative function is
ln bracket 1 plus x
So equals
ln 1 plus 1
minus ln 1 plus 0
So final result equals
ln2 minus 0 equals ln2
It's our final limit
Try to understand the question
means using the idea of definite integral
Try to find our limit
Now look at Question 2
Question 2 means
try to find the limit
Limit n tends to positive infinity
The first term
look at the characteristic
Try to find the rule
Square root of 4 n square minus 1
The second term
4 n square minus 4
blah blah blah
The last term
4 n square minus n square
Compare the question 1
How to find it
Yes
taking out the interval distance 1 over n
And then find i
What is changeable
4 n square
doesn't change
Changeable here
1 4
next
Yes 9
You are clever
Next
16
until n square
1 4 9 16 means i square
So we have the idea
We can write it in this step
Try to find
Try to find what
Yes
interval distance
So taking out this term 1 over n
1 over n is our interval distance
How to write it
Write it how many terms
1 2 3 4 … n
so there are n terms
In the similar idea
if you write it
0 plus 0 plus 0
It’s wrong
Using the idea of
definite integral means the limit idea
So we can write it
Taking n out
Square root means taking n square out
Square root n square means
1 over n
Square and square root
together become n
So now look at the first term
4 n square minus 1
taking out n square
The first becomes 4
The second becomes 1 over n
bracket square
Similar meaning
the second term
becomes 2 over n
bracket square
until the last term
You can find it
Yeah
this is our interval distance
How about ξi
1 over n
2 over n
n over n
yes
1 2 3 until n
So the 1 over n
2 over n
these terms are changeable
Changeable means our ξi
So we can write it
Yes
4 minus 1 over n
bracket square.
Pay attention to i
At this time
we find it ξi
ξi means 4 minus ξi square
ξi means our xi
So the summation
corresponding function
we can find it interval
corresponding function becomes
1 over square root of 4 minus x square
So now how to write it
The lower limit and the upper limit
Do you remember
Yes
1 over n
It is our interval distance
In the first interval
the left end point means 0 over n
The left point ok 0 over n
Another point
1 over n until ok
so i minus 1 over n
i over n
continue
We can find it
1 over n is our interval distance
So how to write it
Look at the lower limit
0 over n is 0
So it is our a equals 0
How about the upper limit
You can think it by yourself
Yes
n over n means 1
So it is our upper limit
So from 0 to 1
we can finish this
Together
write it like this ok
Limit summation means definite integral
from 0 to 1
The corresponding
the summation function
we can write it the integral function
So we do
this equals π over 6
It is our final limit
equals π over 6
So the definition of definite integral
gives us some idea
Try to find the limit
The class is over
Try to understand
See you next time
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